Knowledge Bank

“The lowest-energy states of various symmetries for the linear $CH2$ radical, with a C-H bond length of 1.03\AA have been calculated as a six-electron problem in LCAO/MO/CI approximation: Preliminary results show that the state of lowest energy has symmetry; that the lowest $\mathrm{<mrow\; data-mjx-texclass="ORD">3</mrow>}\Pi u$ state is 20.2 eV higher in energy; and, so far no allowed transitions with energies less than 6 eV between separate electronic states of the linear molecule have been found.”